2x^-8x^2+5x-20=0

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Solution for 2x^-8x^2+5x-20=0 equation: 



2x^-8x^2+5x-20=0

We add all the numbers together, and all the variables

-8x^2+7x-20=0

a = -8; b = 7; c = -20;
Δ = b2-4ac
Δ = 72-4·(-8)·(-20)
Δ = -591
Delta is less than zero, so there is no solution for the equation

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